(2x-4)^2-4=4(x-1)(x-3)

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Solution for (2x-4)^2-4=4(x-1)(x-3) equation: 



(2x-4)^2-4=4(x-1)(x-3)

We move all terms to the left:

(2x-4)^2-4-(4(x-1)(x-3))=0

We multiply parentheses ..

-(4(+x^2-3x-1x+3))+(2x-4)^2-4=0



We calculate terms in parentheses: -(4(+x^2-3x-1x+3)), so:

4(+x^2-3x-1x+3)

We multiply parentheses

4x^2-12x-4x+12

We add all the numbers together, and all the variables

4x^2-16x+12

Back to the equation:

-(4x^2-16x+12)



We get rid of parentheses

-4x^2+16x+(2x-4)^2-12-4=0

We add all the numbers together, and all the variables

-4x^2+16x+(2x-4)^2-16=0

We move all terms containing x to the left, all other terms to the right

-4x^2+16x+(2x-4)^2=16

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